what is the calculation of the ground state energy of the O^7+ hydrogen-like ion. can your answer be in Ve and to an approriate number of significant figures please.
To calculate the ground state energy of the O^7+ hydrogen-like ion, we can use the formula for the energy of a hydrogen-like ion:
Energy = - (Z^2 * (13.6 eV)) / n^2
In this formula, Z represents the atomic number of the ion, and n is the principal quantum number representing the energy level. For the O^7+ ion, Z is 8 (atomic number of oxygen), and we are considering the ground state, which corresponds to n = 1.
Plugging these values into the formula:
Energy = - (8^2 * (13.6 eV)) / (1^2)
= - (64 * 13.6 eV)
= - 870.4 eV
To convert this energy to electron volts (eV) into volts (Ve), we can use the conversion factor: 1 eV = 1.6 x 10^-19 Ve.
Energy in Ve = - 870.4 eV * (1.6 x 10^-19 Ve / 1 eV)
= - 1.39264 x 10^-16 Ve
Rounding to an appropriate number of significant figures, we get:
Energy ≈ - 1.39 x 10^-16 Ve