Factor.
2xy - x²y - 6 + 3x
Is this correct?
(2 + x) (-xy-3)
Thank you! :-)
If you expand your answer, your signs are wrong.
try (x-2)(3-xy)
To factor the given expression 2xy - x²y - 6 + 3x, we can follow these steps:
Step 1: Group the terms in pairs.
2xy - x²y is one pair, and -6 + 3x is another pair.
Step 2: Look for the greatest common factor (GCF) within each group and factor it out.
For the first pair, the GCF is "xy". Factoring it out, we get:
xy(2 - x).
For the second pair, we don't see a clear GCF, but we can factor out a "1". So, the second pair can be rewritten as:
1(-6 + 3x) or (-6 + 3x).
Step 3: Combine the factored terms from Step 2.
We now have xy(2 - x) - 6 + 3x.
Thus, the factored form of the expression 2xy - x²y - 6 + 3x is:
xy(2 - x) - 6 + 3x.
To factor the given expression 2xy - x²y - 6 + 3x, we can look for common factors and grouping.
First, let's group the terms:
(2xy - x²y) + (3x - 6)
Now, let's factor out the common factors from each group:
xy(2 - x) + 3(x - 2)
Now, we can factor out the common factors from both terms:
xy(2 - x) + 3(x - 2) = xy(2 - x) + 3(-1)(x - 2)
Finally, we can simplify further:
xy(2 - x) - 3(x - 2)
Hence, the correct factored form of the expression 2xy - x²y - 6 + 3x is xy(2 - x) - 3(x - 2).