A person has far points 8.44cm from the right eye and 12.2cm from the left eye. WRite a presciption for the powers of the corrective lenses.
Please help i tried to read to book and my notes but it doesnt show how to do this problem.
http://www.owlnet.rice.edu/~phys126/Labs/expt04.pdf
I think if I remember correctly, you want fcorrective= -far distance.
Look in the above physics lab, it has a short discussion of it.
To write a prescription for the powers of corrective lenses, you can use the formula:
Power = 1 / focal length
In this case, the focal length can be approximated using the far points, assuming the corrective lenses would move the far points to infinity. So, the formula becomes:
Power = 1 / far distance
For the right eye, the far point is given as 8.44 cm. To get the power of the corrective lens for the right eye, you can calculate:
Power_right = 1 / 8.44 cm
Similarly, for the left eye, the far point is given as 12.2 cm. The power of the corrective lens for the left eye can be calculated as:
Power_left = 1 / 12.2 cm
To convert the powers from cm to diopters (the unit used for lens prescriptions), you need to divide the powers by 100.
So, the prescription for the right eye would be:
Power_right = 1 / 8.44 cm = 0.1181 D
And the prescription for the left eye would be:
Power_left = 1 / 12.2 cm = 0.08197 D
Please note that this is a simplified calculation based on the given information. It's always best to consult an eye care professional for an accurate prescription.