A solution is prepared by dissolving 0.20 mol of acetic acid and 0.20 mol of ammonium chloride in enough water to make 1.0 L of solution.

Question

A solution is prepared by dissolving 0.20 mol of acetic acid and 0.20 mol of ammonium chloride in enough water to make 1.0 L of solution.

Find the concentration of ammonia in the solution.

Answer 1

I've never seen a problem like this. As an answer, how about zero NH3.

Answer 2

To find the concentration of ammonia in the solution, we need to know the dissociation reaction of ammonium chloride in water.

The dissociation reaction of ammonium chloride (NH4Cl) in water is as follows:

NH4Cl → NH4+ + Cl-

From the reaction, we can see that for every 1 mole of ammonium chloride (NH4Cl) dissolved in water, it produces 1 mole of ammonia (NH4+) ions.

Given that the solution contains 0.20 moles of ammonium chloride, this means that there are also 0.20 moles of ammonia ions in the solution.

Now, we need to find the concentration of ammonia in the solution, denoted as [NH4+]. Concentration is defined as the amount of solute dissolved in a given volume of solution.

The concentration can be calculated using the formula:

Concentration = Amount of solute / Volume of solution

In this case, the amount of solute is 0.20 moles of ammonia ions (NH4+) and the volume of the solution is given as 1.0 L.

Therefore, the concentration of ammonia in the solution is:

Concentration = 0.20 mol / 1.0 L = 0.20 M (Molar)

So, the concentration of ammonia in the solution is 0.20 M.

Answer 3

To find the concentration of ammonia in the solution, we need to understand the reaction that occurs between acetic acid (CH3COOH) and ammonium chloride (NH4Cl) in water.

The reaction is as follows:
CH3COOH + NH4Cl → NH3 + CH3COONH4

This means that one molecule of acetic acid reacts with one molecule of ammonium chloride to form one molecule of ammonia (NH3) and one molecule of ammonium acetate (CH3COONH4).

From the given information, we have 0.20 mol of acetic acid and 0.20 mol of ammonium chloride. Since the reaction is 1:1, it means that 0.20 mol of ammonia is also formed.

Now, we need to find the concentration of ammonia in the solution. Concentration is defined as the amount of solute (in moles) divided by the volume of the solution (in liters).

We know that the total volume of the solution is 1.0 L, and we have 0.20 mol of ammonia.

Therefore, the concentration of ammonia in the solution can be calculated as:
Concentration of ammonia = (amount of ammonia / volume of solution)
= (0.20 mol / 1.0 L)
= 0.20 mol/L

So, the concentration of ammonia in the solution is 0.20 mol/L.