How do I put this equation in slope intercept form?
2. 2x + 3y = 6
Slope intercept form is
y = mx + b
Subtract 2x from both sides and then divide both sides by 3.
I hope this helps. Thanks for asking.
To put the given equation, 2x + 3y = 6, into slope-intercept form (y = mx + b), follow these steps:
1. Begin with the equation: 2x + 3y = 6.
2. To isolate the y-term, subtract 2x from both sides of the equation.
This results in: 3y = -2x + 6.
3. Next, divide both sides of the equation by 3 to solve for y.
This yields: y = (-2/3)x + 2.
Now the equation is in slope-intercept form (y = mx + b), where the coefficient of x (-2/3) represents the slope and the constant term (2) represents the y-intercept.