y intercept:
3x^2+18x
0=3x^2+18x
from here im lost
what do you want to do?
solve it ?
find the y-intercept ?
yes find y intercept
then let x = 0
so y = 3(0) + 18(0) = 0
the y-intercept is 0, the line runs through the origin.
sorry i meant the x intercept
x intercept:
y = 3x^2+18x
0 = 3x^2+18x
3x is common to both terms on the right: factor it out.
0 = 3x(x + 6)
If 2 values are multiplied together and the product is 0, then one or both of the values must be 0.
3x = 0 and/or x + 6 = 0
Take it from there.
To find the y-intercept of a quadratic equation, you need to consider the equation when x is equal to zero.
In your case, the equation is:
0 = 3x^2 + 18x
To solve this equation, you can factor out the greatest common factor, which is 3:
0 = 3(x^2 + 6x)
Now, you have a simplified equation:
0 = 3(x(x + 6))
To find the values of x that make this equation true, you set each factor equal to zero:
1. From x = 0:
3(0 + 6) = 0
18 = 0 (which is not true)
2. From x + 6 = 0:
x = -6
So, the x-intercept (or the value of x when y equals zero) is x = -6.
To find the y-intercept, substitute the value of x = 0 back into the original equation:
y = 3(0)^2 + 18(0)
y = 0 + 0
y = 0
Therefore, the y-intercept is y = 0.