Write the standard form of the equation of the circle that passes through (0,4) and has its center at (-3,-1).
(x-h)^2 + (y-k)^2 = r^2
(x+3)^2 + (y+1)^2 = r^2
r^2 = d
d = sqrt(x2-x1)^2 +(y2-y1)^2
d = sqrt(-3-0)^2 + (-1-4)^2
d = 3^2 + -5^2
d = sqrt34
(x+3)^2 + (y+1)^2 = r^2
(x+3)^2 + (y+1)^2 = sqrt34 <--(answer)
I got half off, she just circled the sqrt34 part
for a circle with centre (h,k) and radius r
the standard form is
(x-h)^2 + (y-k)^2 = r^2
your right side should have been 34 not √34
BTW, an easier and quicker way would be to start with
(x+3)^2 + (y+1)^2 = r^2 , now sub in (0,4)
9 + 25 = d^2 = 34
put that back in, done!