Tell whether the relation is a function. Explain your answer.
(-6,-3), (-4,-2), (-2,0), (2,0), (4,-2), (6,-3).
To determine whether the relation is a function, we need to check if each x-value in the set of ordered pairs maps to exactly one y-value.
In this relation:
(-6, -3), (-4, -2), (4, -2), (6, -3) each x-value maps to a unique y-value.
However, the ordered pairs (-2, 0) and (2, 0) have the same x-value, but different y-values. Therefore, the relation is not a function because there are two different y-values assigned to the x-value 0.
To determine whether a relation is a function, we need to check if there are any duplicated x-values. If there are no duplicates, then the relation is a function.
Let's examine the given relation:
(-6, -3),
(-4, -2),
(-2, 0),
(2, 0),
(4, -2),
(6, -3).
Looking at the x-values, we notice that there are no duplicates. Each x-value is unique. Therefore, there are no two inputs that map to more than one output. Since there are no duplicated x-values, we can conclude that the given relation is a function.
In a function, for any given value of x, there can be only one value of y
since all the values of x are different, the points given do form a function.
had there been another point such as (2,3)
for the given value of x=2 there would have been 2 different values of y, namely 0 and 3
thus it would NOT be a function.
BTW, as to my reply to you from a previous post, why don't you just substitute the given values in your inequation, if it works ... ?
Thanks for the reply =)
And about the previous post, I did substitute it and from what I got it is the solution for the ineaqulity...