I have a math CRCT test today and I needed some help on a last minute review problem.
Can someone please explain how to solve this?
1. 12x-3+6x-2=31
-MC
add the x's and "move" the constants to the other side ---->
12x+6x = 31 + 3 + 2
18x = 36
divide both sides by 18
18x/18 = 36/18
x = 2
Combine like terms.
18x -5 = 31
Add 5 to both sides.
18x = 36
Divide by 18.
x = 2
I hope this helps. Thanks for asking.
Thanks! I realllyyy hope I pass this!!
-MC
To solve this equation, you need to combine like terms and isolate the variable x.
Here's how you can solve it step by step:
1. Start by combining the like terms on both sides of the equation. Add the coefficients of x together and combine the constants:
12x + 6x - 3 - 2 = 31
This simplifies to:
18x - 5 = 31
2. Now, you want to isolate the x term by getting rid of the constant on the left side. To do this, add 5 to both sides of the equation:
18x - 5 + 5 = 31 + 5
This simplifies to:
18x = 36
3. Finally, to solve for x, divide both sides of the equation by the coefficient of x, which is 18:
18x / 18 = 36 / 18
This simplifies to:
x = 2
So the solution to the equation is x = 2.
Make sure to check your answer by substituting x = 2 back into the original equation and ensuring that it satisfies the equation.