I have a math CRCT test today and I needed some help on a last minute review problem.

Can someone please explain how to solve this?

1. 12x-3+6x-2=31

-MC

add the x's and "move" the constants to the other side ---->

12x+6x = 31 + 3 + 2
18x = 36
divide both sides by 18
18x/18 = 36/18
x = 2

Combine like terms.

18x -5 = 31

Add 5 to both sides.

18x = 36

Divide by 18.

x = 2

I hope this helps. Thanks for asking.

Thanks! I realllyyy hope I pass this!!

-MC

To solve this equation, you need to combine like terms and isolate the variable x.

Here's how you can solve it step by step:

1. Start by combining the like terms on both sides of the equation. Add the coefficients of x together and combine the constants:

12x + 6x - 3 - 2 = 31

This simplifies to:

18x - 5 = 31

2. Now, you want to isolate the x term by getting rid of the constant on the left side. To do this, add 5 to both sides of the equation:

18x - 5 + 5 = 31 + 5

This simplifies to:

18x = 36

3. Finally, to solve for x, divide both sides of the equation by the coefficient of x, which is 18:

18x / 18 = 36 / 18

This simplifies to:

x = 2

So the solution to the equation is x = 2.

Make sure to check your answer by substituting x = 2 back into the original equation and ensuring that it satisfies the equation.