A bag contains 5 red, 3 green, 12 white and 7 blue marbles. One is drawn at random. With is the probability it is green if it is not red or blue?
This conditional probability
the formula is
P(A│B), read the prob of A given B
= P(A and B)/P(B)
in your case Prob(A) is Prob(green)
B is "not red or blue"
so find Prob(green AND "not red or blue")
and Prob(not red or blue) and sub into the formula
There'sa100 red 50 green and 50 blue beads in a jar what's the probability that I'll pull out a blue bead
To calculate the probability of drawing a green marble, given that it is not red or blue, we need to determine the total number of marbles that are not red or blue and the number of green marbles among them.
First, add up the number of red and blue marbles: 5 red + 7 blue = 12 marbles.
Subtracting this from the total number of marbles gives us the count of marbles that are not red or blue: 5 red + 7 blue + 3 green + 12 white = 27 marbles - 12 = 15 marbles.
Out of these 15 marbles, we need to find the number of green marbles. From the given information, we know that there are 3 green marbles.
Therefore, the probability of drawing a green marble, given that it is not red or blue, is 3/15 or 1/5.
So, the probability is 1/5 or 0.2, which is equivalent to 20%.