Can someone find the sum for this equation please.
(X^2)/(X^2-16)=(5X+4)/(X^2-16)
I don't think it is finding the sum, but I can simplify the equation.
(X^2)/(X^2-16)=(5X+4)/(X^2-16)
First, multiply both sides by X^-16.
X^2 = 5X+4
Subtract 5X+4 from both sides.
X^2-5X-4 = 0
However, this equation cannot be factored. If the original equation was
(X^2)/(X^2-16)=(5X-4)/(X^2-16)
Then it would simplfy to
X^2-5X+4 = 0
Which could be factored into
(X-1)(X-4) = 0
I hope this helps. Thanks for asking.
To find the sum for the equation X^2-5X-4 = 0, you can use the quadratic formula or complete the square. I will explain how to use the quadratic formula.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In the equation X^2-5X-4 = 0, we can identify that a = 1, b = -5, and c = -4.
Plugging these values into the quadratic formula, we have:
x = (-(-5) ± √((-5)^2 - 4(1)(-4))) / (2(1))
Simplifying further:
x = (5 ± √(25 + 16)) / 2
x = (5 ± √41) / 2
Therefore, the sum for this equation would be the sum of the two solutions:
(5 + √41) / 2 and (5 - √41) / 2
These are the two values that satisfy the equation X^2-5X-4 = 0.