Write an equation. The sum of 2 consecutive integers 48.

Correct me if I'm wrong, but there are no two consecutive integers that add up to 48. However, if you were finding two consecutive NUMBERS that add up to 48, your equation would look like this:

x + (x+1) = 48

x being the first number, (x+1) being the consecutive number.

Hope this helps!

Thanks, you helped a lot! My teacher isn't the brightest crayon in the box and that's what she typed on the worksheet.

consecutive: one after the other

so let the first integer be x
then the next consecutive integer has to be x+1
now translate
" The sum of 2 consecutive integers is 48"
x + x+1 = 48
2x = 47
x = 47/2 which is not an integer.

so your problem has no solution

(one can see that right from the start.
For any two consecutive integers, one would have to be even and the other one odd. And of course, the sum of an even plus an odd is always odd)

No problem :) glad I could help!

To find an equation that represents the sum of two consecutive integers equaling 48, we can assign variables to the integers. Let's call the first integer "x", and the second integer "x+1" since the second integer is always one more than the first.

The equation for the sum of these two consecutive integers will be:

x + (x+1) = 48

To solve this equation, we have to eliminate the parentheses by combining like terms:

2x + 1 = 48

Next, we isolate the variable on one side of the equation by subtracting 1 from both sides:

2x = 48 - 1
2x = 47

Finally, we can solve for x by dividing both sides of the equation by 2:

x = 47/2
x = 23.5

Since the first integer must be a whole number, we can conclude that there are no two consecutive integers whose sum is exactly 48.