hi how would we solve a question like this?
for the curve with eq'n
2x^2 - x - 1
y= _______________
x^2 - 2x - 3
determina all x- and y-intercepts
I assume you meant
y = (2x^2 - x - 1)/(x^2 - 2x - 3)
both top and bottom factor but there is no advantage gained.
However, the bottom (x-3)(x+1) tells you there are two asymptotes, one at x=3 and another at x=-1
for the y-intercept, let x=0
so y= 1/3
for the x intercept, let y=0
then (2x+1)(x-1)=0
which gives x intercepts at -1/2 and 1