You pushed a 1 kg box on floor where= 0.3. If the force you applied was 5 N, will the box move?

Question

You pushed a 1 kg box on floor where= 0.3. If the force you applied was 5 N, will the box move?

m = 1kg
u= 0.3
Fapp= 5 N

Ff= (0.3)(1) (9.81)
Ff = 2.943 N

So therefore the box would move because the frictional force is less than the applied force.

Did I answer this correctly?

Answer 1

Lena, you answered the question right. Good job. The force of friction F(f) = (mew)N. You set up the problem correctly.

One thing to keep in mind is that the applied force might not necessarily be directly opposite the frictional force. The box could be pushed at an angle, making the problem much more complicated.

Answer 2

Oh ok. Thanks :)

Answer 3

Yes, your answer is correct. The frictional force can be calculated by multiplying the coefficient of friction (u) by the normal force (m * g, where g = 9.81 m/s² is the acceleration due to gravity). In this case, the frictional force is 2.943 N, which is less than the applied force of 5 N. As a result, the box will move.

Answer 4

Yes, you answered the question correctly. Based on the values you provided, you correctly calculated the frictional force (Ff) as 2.943 N. Since the applied force (Fapp) is 5 N, and Ff is less than Fapp, the box will indeed move. Good job!