4x^2-45x+50=0
(x -10)(4x -5) = 0
x = 10 or 5/4
To find the solutions to the quadratic equation 4x^2 - 45x + 50 = 0, you can use the quadratic formula.
The quadratic formula states that for any quadratic equation of the form ax^2 + bx + c = 0, the solutions for x can be obtained using the following formula:
x = (-b ± √(b^2 - 4ac))/(2a)
In the given equation, a = 4, b = -45, and c = 50. By substituting these values into the quadratic formula, we can find the solutions:
x = (45 ± √((-45)^2 - 4*4*50))/(2*4)
Simplifying further:
x = (45 ± √(2025 - 800))/8
x = (45 ± √1225)/8
Now, let's calculate the discriminant inside the square root:
√1225 = 35
Therefore:
x = (45 ± 35)/8
There are two possible solutions:
x1 = (45 + 35)/8 = 80/8 = 10
x2 = (45 - 35)/8 = 10/8 = 5/4
Hence, the solutions to the quadratic equation 4x^2 - 45x + 50 = 0 are x = 10 and x = 5/4.