Write the equation of the line passing through the given point with the indicated slope. Give your results in slope-intercept form. Point: (0,5) Slope:m=3/5. Show work
Well, youknow the form is y= mx+b
you are given m. You are given a point (0,5) Put that point into the equation, and solve for b.
To write the equation of a line in slope-intercept form (y = mx + b), you need to know the slope (m) and a point (x, y) that lies on the line. In this case, you are given the slope (m = 3/5) and the point (0, 5).
To find the equation, substitute the values of the slope and the coordinates of the given point into the equation and solve for b:
y = mx + b
5 = (3/5)(0) + b
5 = 0 + b
b = 5
Now that you have the value of b, you can write the equation:
y = (3/5)x + 5
So, the equation of the line passing through the point (0, 5) with a slope of 3/5 is y = (3/5)x + 5.
The slope-intercept form of a linear equation is given by y = mx + b, where m represents the slope and b represents the y-intercept.
In this case, the given slope (m) is 3/5, and the given point is (0, 5).
We can substitute the values of the slope and the coordinates of the point into the equation and solve for b:
5 = (3/5)(0) + b [Substituting the values]
5 = 0 + b [Simplifying]
b = 5 [Simplifying]
Therefore, the value of b is 5.
Now we have the slope (m = 3/5) and the y-intercept (b = 5), so we can write the equation of the line passing through the given point as:
y = (3/5)x + 5
So, the equation in slope-intercept form is y = (3/5)x + 5.