evaluate each function for the value specified.fx+x2-7x+10;
find (a)f(0),(b)f(5),and(c)f(-2).
can any one help me withthis i have not the first clue how to begin here.
What you wrote is nonsense.
Did you mean
f(x)=x2-7x+10 ?
If so, f(0)= put zero in for x, so it equals 10.
f(5)=5^2 -7*5 +10
yes the problem was f(x)=x2-7x+10 but it had a small 2 by the x and we have to fins (a) f(0),(b) f(5) and (c)f (-2) and i have no clue how to do this
Okay, yes...any time you see f(number), that just means you plug in the number for x, and solve.
f(0) means: do this equation with 0 substituted for x.
f(5) means: do this equation with 5 substituted for x.
etc.
To evaluate each function for the specified values, you simply need to substitute the given values into the function and calculate the result.
For the function f(x) = x^2 - 7x + 10:
(a) To find f(0), substitute 0 for x:
f(0) = (0)^2 - 7(0) + 10 = 0 - 0 + 10 = 10
(b) To find f(5), substitute 5 for x:
f(5) = (5)^2 - 7(5) + 10 = 25 - 35 + 10 = 0
(c) To find f(-2), substitute -2 for x:
f(-2) = (-2)^2 - 7(-2) + 10 = 4 + 14 + 10 = 28
So, f(0) = 10, f(5) = 0, and f(-2) = 28.
To evaluate each function for the specified values, we will substitute the given values into the function and calculate the result.
The function is f(x) = x^2 - 7x + 10.
(a) To find f(0), we substitute x = 0 into the function:
f(0) = (0)^2 - 7(0) + 10
= 0 - 0 + 10
= 10
Therefore, f(0) = 10.
(b) To find f(5), we substitute x = 5 into the function:
f(5) = (5)^2 - 7(5) + 10
= 25 - 35 + 10
= 0
Therefore, f(5) = 0.
(c) To find f(-2), we substitute x = -2 into the function:
f(-2) = (-2)^2 - 7(-2) + 10
= 4 + 14 + 10
= 28
Therefore, f(-2) = 28.
So, the evaluations are:
(a) f(0) = 10
(b) f(5) = 0
(c) f(-2) = 28