What is ksp for lithium carbonate?
I got an answer of 2.40 x 10^-4 but i need to check that answer with somebody who can work this out
No, it is Li2CO3 and not Li2(CO3)2 and it isn't 0.0055 either. I goofed. Let me do it right. (The ratio is 2:1)
Li2CO3 ==> 2Li^+ + CO3^=
Ksp = (Li^+)^2*(CO3^=) =
(2*7.4 x 10^-2)^2(7.4 x 10^-2) =
4(7.4 x 10^-2)^3 = 0.00162 which I would round to 0.0016 to two s.f.
Check my work.
You didn't post anything to work. In addition, I thought Li2CO3 was pretty cotton pickin' soluble. AND I can't find it listed in any of my Ksp tables. The Merck Index says about 1 gram will dissole in 78 mL cold water.
the question says: the solubility of Li2CO3 is 7.4 x 10^-2 mol/L, find ksp. I also couldn't find it on any of my talbes but it seems like its a doable question
OK. From the data you provided (it wasn't in the first post),
Shouldn't Ksp just be (7.4 x 10^-2)^2 = ??
I don't get 2.4 x 10^-4 but more like 5.548 x 10^-3 which rounds to 0.0055 to two s.f.
I thought it couldn't just be squared because we have an uneven ratio (2:3)
To determine the solubility product constant (Ksp) for lithium carbonate (Li2CO3), you need the balanced equation for its dissociation/solubility in water. The equation is as follows:
Li2CO3(s) ⇌ 2Li+(aq) + CO3^2-(aq)
From this equation, you can see that one mole of lithium carbonate dissociates into two moles of lithium ions (Li+) and one mole of carbonate ions (CO3^2-).
To calculate the Ksp for Li2CO3, you need to know the molar solubility of the compound. The molar solubility is the amount of substance (in moles) that dissolves per liter of solution at equilibrium. However, the given answer you provided seems to be the Ksp value itself, rather than the molar solubility.
To determine the Ksp, you would need the molar solubility value. If you have the concentration of lithium ions or carbonate ions at equilibrium, you can calculate the molar solubility of Li2CO3 and then use it to find the Ksp.
If you only have the Ksp value (2.40 x 10^-4), without any additional information, it would be difficult to check the answer. The Ksp value is typically experimentally determined and can vary slightly depending on the source.
If you have more information or equations relating to the solubility of lithium carbonate, please provide them so that I can assist you further in checking the answer.