An electromagnetic wave has a wavelength of 6.2 x 10^14 m. What is the frequency of the wave?
A. 2.0 x 10^6 Hz
B. 4.8 x 10^-7 Hz
C. 1.8 x 10^24 Hz
D. 5.3 x 10^-22 Hz
I got B..?
When the currents in two parallel metal conductors are in the same direction, the conductors ____ each other.
A. attract
B. repel
C. do no exert any force
D. exert forces that are perpendicular to
I got D..?
first right,second wrong.
6. A current-‐carrying conductor is kept at right angles to the direction of a magnetic field. What happens to the force acting on the wire if the strength of the magnetic field doubles?
A current-‐carrying conductor is kept at right angles to the direction of a magnetic field. What happens to the force acting on the wire if the strength of the magnetic field doubles?
To find the frequency of an electromagnetic wave, you can use the equation:
frequency = speed of light / wavelength
The speed of light in a vacuum is approximately 3.0 x 10^8 meters per second.
In this situation, the given wavelength is 6.2 x 10^14 meters. Therefore, to find the frequency, we can substitute the values into the equation.
frequency = (3.0 x 10^8 m/s) / (6.2 x 10^14 m)
Now, when you divide these two values, you will get the answer in hertz (Hz), which represents the frequency.
Calculating it:
frequency = 4.8 x 10^-7 Hz
Therefore, your answer of B. 4.8 x 10^-7 Hz is correct.
For the second question, when the currents in two parallel metal conductors are in the same direction, the conductors actually attract each other. So, the correct answer is A. attract.