A line passes through (2,-1) and 8,4). How do you write an equation for the line in point-slope form?
Never mind, I already got it: y + 1 = 5/6 9x + 2). Now how do you rewrite this equation in standard form using integers?
never mind, i got that too.
To write the equation of a line in point-slope form, you need two pieces of information: a point on the line and the slope of the line.
Given the points (2,-1) and (8,4), we can find the slope of the line by using the formula:
slope (m) = (change in y) / (change in x)
Let's calculate the slope first:
change in y = 4 - (-1) = 5
change in x = 8 - 2 = 6
slope (m) = 5 / 6
Now that we have the slope (m) and a point (2, -1), we can write the equation of the line in point-slope form.
The point-slope form equation is given by:
(y - y₁) = m(x - x₁)
Where (x₁, y₁) is a point on the line, and m is the slope of the line.
Substituting the values we have:
(y - (-1)) = (5/6)(x - 2)
Simplifying the equation further:
(y + 1) = (5/6)(x - 2)
This is the equation of the line in point-slope form.