ok i really need help. like really bad. cant figure it out. ok here it is.

a color blind man marries a woman with normal vision. of their three daughters, one is color blind. one of their two sons is also colorblind. what are the genotypes of the parents?

please help me its confusing!

color blindness is x-linked recessive. The father is obviously xy, where x means the bad gene for color blindness. Now, what is the mother? Since one of the daughters is color blind, the mother must also have bad gene. She is heterozygous...one good and one bad...Xx. If the mother had both good genes, none of the kids would be color blind, and if the mother had both bad genes, ALL the kids would be color blind. Do you see this?

ya i see it now. kinda... lol. thanks.

wait couldn't the mom and the dad both be xy? casue 2/5ths of there kids are color blind

nope. y is the male gene. Mom can't be xy...then she'd be a he!!

To determine the genotypes of the parents, we need to understand how color blindness is inherited. Color blindness is an X-linked recessive trait, which means it is carried on the X chromosome.

In this scenario, the father is color blind and has the genotype XY, where X represents the chromosome carrying the color blindness gene.

Now, let's consider the mother. Since one of their daughters is color blind, it means the mother must carry the color blindness gene. In this case, the mother is a carrier and has the genotype Xx, where one X chromosome carries the color blindness gene (x) and the other X chromosome carries the normal vision gene (X).

If the mother had both normal vision genes, none of their children would be color blind. If the mother had two color blindness genes, all of their children would be color blind. Thus, the mother being a carrier (Xx) explains why only some of their children are color blind.

In summary, the genotype of the father is XY (color blind) and the genotype of the mother is Xx (carrier).