The sum of the ages of the three Romano brothers is 63. If their ages can be represented as consecutive integers, what is he age of the middel brother?
let the middle brother's age be x
then the oldest is x+1
and the youngest is x-1
x-1 + x + x+1 = 63
solve for x to get middle brother's age.
63 is three times the average age (which is that of the middle brother), so that age much be 21. The ages of all three are therefore 20, 21 and 22.
To find the age of the middle brother, we need to use algebra to solve the problem. Let's call the age of the middle brother x.
According to the problem, the ages of the three brothers can be represented as consecutive integers. So we can represent the ages of the three brothers as x-1, x, and x+1.
The sum of their ages is given as 63, so we can write an equation:
(x-1) + x + (x+1) = 63
Let's solve this equation step by step:
Combining like terms, the equation becomes:
3x = 63
Dividing both sides of the equation by 3, we get:
x = 21
Therefore, the age of the middle brother is 21.