what is the probability of winning a lottery game where the winning number is made of 6digits from 0-9 chosen at random?

i do not undestand how to solve please help

It is not just a combination of 10 taken 6 at a time because the digits can be repeated, like 2 2 2 3 3 3

Also order matters
So
what is the chance of the first digit being right?
1/10
then the second one?
1/10 not 1/9 because we can use the same digit again
then the third?
1/10
and so on
so
(1/10)^6 = one out of a million

To calculate the probability of winning a lottery game where the winning number is made of 6 digits chosen at random from 0-9, you need to consider two things: the total number of possible outcomes and the number of favorable outcomes (i.e., the winning number).

Step 1: Determine the Total Number of Possible Outcomes
In this case, each digit can range from 0 to 9, so there are 10 options for each digit. Since there are 6 digits in the winning number, the total number of possible outcomes is calculated by multiplying 10 by itself six times (10^6).

Total Number of Possible Outcomes = 10^6 = 1,000,000

Step 2: Determine the Number of Favorable Outcomes
In a lottery game, there is only one winning number. Therefore, the number of favorable outcomes is 1.

Number of Favorable Outcomes = 1

Step 3: Calculate the Probability
The probability of winning the lottery game is the ratio of the number of favorable outcomes to the total number of possible outcomes.

Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes

Substituting the values:

Probability = 1 / 1,000,000

Simplifying the fraction, the probability is:

Probability = 1 in 1,000,000

So, the probability of winning this particular lottery game is 1 in 1,000,000.