I've never seen a problem like this, please help.
I think we have the number part right but what would the unit be once the math is done?
Please show me how you came up with the answer so I will know for next time.
30 miles/1 ton x 5280 feet/1 mile x 1 hour/60 minutes x 1 minute/60 seconds
I really don't get this. Thank you
Are you sure that does not start out as 30 miles/hr? If so, you would end up after doing the multiplication with the equivalent speed in ft/sec.
Otherwise, it is 44 ft hr/ton*sec, which makes no sense
what we have for an equation is what I put down. Thanks for the help.
drwls I am dippy!! It should have been 30 miles/ 1 hour not 1 ton. That was part of the next question.
Sure, I'd be happy to help you understand this problem and how to find the correct unit.
To begin, let's break down the problem step by step:
1. Start with the given value: 30 miles/1 ton.
2. Next, we want to convert miles to feet. We know that there are 5280 feet in 1 mile. So, we multiply our current value by the conversion factor: 30 miles/1 ton x 5280 feet/1 mile. This will cancel out the "miles" unit and leave us with "feet" as the unit.
3. Now, let's move on to converting the time. We are given the conversion factor of 1 hour/60 minutes. So, we multiply our result from step 2 by this conversion factor: 30 miles/1 ton x 5280 feet/1 mile x 1 hour/60 minutes. This will cancel out the "minutes" unit and leave us with "hours" as the unit.
4. Finally, we convert the remaining "hours" to "seconds". We know that there are 60 minutes in 1 hour, and 60 seconds in 1 minute. Multiplying our result from step 3 by the conversion factor of 1 minute/60 seconds will cancel out the "minutes" unit and give us the desired unit of "seconds".
So, when we multiply the given values and conversion factors together:
30 miles/1 ton x 5280 feet/1 mile x 1 hour/60 minutes x 1 minute/60 seconds
The final unit will be "seconds". This means that the original value of 30 miles/1 ton, once multiplied and converted appropriately, represents the number of seconds.
I hope this explanation clarifies the problem and the process for you. Remember, when dealing with unit conversions, you can use conversion factors to cancel out unwanted units and obtain the desired unit for your final result.