Solve by the elimination method.
5r-3s=2
3r 5s =42
r=-40
is this right.
4x+5y=7
5x-4y=5
Decide whteher the pair of line is parallel, perpindular, or n
I said is was parallel. Tell me if this right.
in your first question, you found only the one variable, you still have to find s
Besides that, you have a typo in the second equation.
in your second problem,
the slope of the first equation is -4/5
the slope of the second one is 5/4
notice they are negative reciprocals of each other.
What did you learn about that situation?
-3(7r-5)=-48
can u help me solve this problem
To solve the system of equations using the elimination method, you need to eliminate one variable by manipulating the equations.
For the first system of equations:
Equation 1: 5r - 3s = 2
Equation 2: 3r + 5s = 42
To eliminate one variable, you can multiply both sides of Equation 1 by 3 and Equation 2 by 5:
3 * (5r - 3s) = 3 * 2
5 * (3r + 5s) = 5 * 42
This leads to the following equations:
15r - 9s = 6
15r + 25s = 210
Now, subtract Equation 1 from Equation 2 to eliminate the variable 'r':
(15r + 25s) - (15r - 9s) = 210 - 6
25s + 9s = 204
34s = 204
s = 6
To determine the value of 'r', substitute the value of 's' in either of the original equations. Let's use Equation 1:
5r - 3(6) = 2
5r - 18 = 2
5r = 20
r = 4
So, the solution to the system is r = 4 and s = 6.
As for the second system of equations:
Equation 1: 4x + 5y = 7
Equation 2: 5x - 4y = 5
To determine if these lines are parallel, perpendicular, or neither, you can compare the slopes of the equations.
The slope-intercept form of a linear equation is y = mx + b, where 'm' represents the slope.
Equation 1 is already in slope-intercept form: y = (-4/5)x + 7/5
Comparing the coefficient of 'x', the slope of Equation 1 is -4/5.
Equation 2 can be rearranged into slope-intercept form: y = (5/4)x - 5/4
Comparing the coefficient of 'x', the slope of Equation 2 is 5/4.
Since the slopes of the two equations are NOT equal, the lines are NOT parallel.
Hence, your answer that the lines are parallel is incorrect.