Solid sodium carbonate reacts with hydrochloric acid to give sodium chloride,carbon dioxide and water.
When writing the ionic equation, do I need to write Na2CO3(s)or do I write CO32-(aq) on the left hand side of the equation?
write it as an ion.
To write the balanced ionic equation for the reaction between solid sodium carbonate (Na2CO3) and hydrochloric acid (HCl), you need to consider the dissociation of the compound in water. Sodium carbonate, as a solid, does not dissociate into ions. Therefore, you should write Na2CO3(s) on the left-hand side of the equation.
The balanced equation for the reaction is:
Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l)
In this reaction, sodium carbonate reacts with hydrochloric acid to produce sodium chloride, carbon dioxide, and water. The carbonate ion (CO32-) is not written separately in the equation because it does not exist as an ion on the left-hand side of the equation.