I am figuring out how many moles of CU2SO4 are in 485.6 grams. How would you set up the proportion for this? What would the answer then be. Thanks. I really need an example to jumpstart this worksheet.
You have to figure the formula mass for this. Get your periodic table out, and look up the atomic mass of Cu, S, and O
Now take two Cu, one S, and 4 O and add them. That is the mass of one mole of Cu2SO4.
Divide that into 485.6 that is how many moles of Cu2SO4 are in that mass.
Are you certain of the form of Cu2SO4? Normally, it is in hydrated form, with a formula such as..
Cu2SO4.5H20
If you are in the lab, you are probably using a hydrated form. If this is just a calculation exercise, ignore this part of reality.
2Cu = 127 g
1S = 32 g
4O = 64 g
so
223 grams per mole
485.6 grams (1 mole/223 g) = 2.18 moles
Thank you so much. That was really easy to understand.
To figure out the number of moles of Cu2SO4 in 485.6 grams, you need to use the molar mass of Cu2SO4 and the given mass.
The molar mass of Cu2SO4 can be calculated by adding up the atomic masses of copper (Cu), sulfur (S), and oxygen (O).
Cu: 63.55 g/mol
S: 32.07 g/mol
O: 16.00 g/mol
So, the molar mass of Cu2SO4 is:
2(63.55 g/mol Cu) + 32.07 g/mol S + 4(16.00 g/mol O) = 159.62 g/mol
Now that you know the molar mass, you can set up a proportion to find the number of moles. The proportion looks like this:
1 mol / 159.62 g = x mol / 485.6 g
To solve for x (the number of moles), cross-multiply:
485.6 g * 1 mol = x mol * 159.62 g
Divide both sides by 159.62 g:
x mol = (485.6 g * 1 mol) / 159.62 g
Now, you can calculate the number of moles:
x mol = 3.041 mol
Therefore, there are approximately 3.041 moles of Cu2SO4 in 485.6 grams.