PLEASE HELP!! I HAVE A TEST TOMORROW!!
if Q=30 uC, q=5.0 uC, and d=30cm, what is the magnitude of the electrostatic force on q in N?
(Ke= 8.99 x 10^9 Nm^2/C^2)
(uC= micro coulombs)
(u= 10^-6)
a. 15
b. 23
c. zero
d. 7.5
e 38
i don't know where to start with this problem. i don't even have a formula if there is one.
Look up Coulombs law.
http://en.wikipedia.org/wiki/Coulomb%27s_law
i left out an important drawing, but i cant get it to copy correctly.
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i used the ''''''''' to hold the spaces
when i do this problem i keep getting 1.49*10^13 does anyone know where i am going wrong K (30*5)/.3^2. Please email me at burtonjoe72@gmail thx
Ah, I see you are dealing with some electrifying physics! Don't worry, I'm here to help you zap through this problem.
The magnitude of the electrostatic force can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Lucky for you, the formula is:
F = (k * |Q*q|) / d^2
Where:
F is the magnitude of the electrostatic force,
k is the electrostatic constant (Ke),
Q and q are the charges (in Coulombs), and
d is the distance between the charges (in meters).
Now let's substitute the given values into the formula:
F = (8.99 x 10^9 Nm^2/C^2 * |30 uC * 5.0 uC|) / (0.30 m)^2
Before we continue, we need to convert the charges to Coulombs since the formula requires SI units. Since 1 uC = 10^-6 C:
F = (8.99 x 10^9 Nm^2/C^2 * |30 x 10^-6 C * 5.0 x 10^-6 C|) / (0.30 m)^2
Now let's simplify:
F = (8.99 x 10^9 Nm^2/C^2 * 1.5 x 10^-4 C^2) / (0.30 m)^2
F = (1.3485 x 10^6 Nm^2) / (0.09 m^2)
F = 14.983 N
Rounding off, the magnitude of the electrostatic force on q is approximately 15 Newtons. So the answer is option a. 15.
Remember, teamwork makes the dream work! Good luck with your test!
To find the magnitude of the electrostatic force on q, you can use Coulomb's Law. Coulomb's Law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's Law is:
F = ( (k * |Q| * |q|) / (d^2) )
where F is the electrostatic force, k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), Q is the charge on one object, q is the charge on the other object, and d is the distance between the charges.
In this question, Q = 30 uC, q = 5.0 uC, and d = 30 cm. However, the unit of distance must be in meters for the formula to work correctly. Therefore, you need to convert 30 cm to meters by dividing it by 100.
Plugging in the values into the formula:
F = ( (8.99 x 10^9 Nm^2/C^2) * (30 x 10^-6 C) * (5.0 x 10^-6 C) ) / ( (30/100)^2 )
Now, perform the calculations step by step:
1. Multiply the charges: (30 x 10^-6 C) * (5.0 x 10^-6 C) = 150 x 10^-12 C^2.
2. Square the distance: (30/100)^2 = 0.09 m^2.
3. Multiply the result of step 1 and the electrostatic constant: (8.99 x 10^9 Nm^2/C^2) * (150 x 10^-12 C^2) = 1.3495 N.
4. Divide the result of step 3 by the result of step 2: 1.3495 N / 0.09 m^2 = 14.9944 N.
Therefore, the magnitude of the electrostatic force on q is approximately 14.99 N.
Since none of the answer choices match exactly, you should round this value to the nearest whole number, giving you the option:
a. 15
So, the answer to the question is a. 15.
F = k |Q q|/d^2 Coulomb's Law
k = 9*10^9 Nm^2/C^2
here
F = 9*10^9 (30^10^-6)(5*10^-6)/(0.30)^2
= 1350 *10^-3/(9*10^-2)
= 150*10^-1
=15 N
1350