KHP is a monoprotic acid with a molar mass of 204.22 g/mol. The titration data are as following.
The average concentration of NaOH solution is
M.
1 2 3
mass of KHP (g) 2.789 2.543 2.612
vol NaOH used (mL) 27.77 23.22 27.12
You didn't ask a question but I assume you are to calculate the molarity of NaOH.
mols KHP = mols NaOH
mols KHP = g/molar mass
mols NaOH = volume NaOH x M NaOH.
Post your work if you get stuck.
2.789 g KHP x (1 mol KHP/204.22 g KHP) = 0.0137 mol KHP
27.77 mL NaOH x (M NaOH) = 0.0137 mol KHP
M NaOH = 0.0137 mol KHP/27.77 mL NaOH = 0.049 M NaOH
2.543 g KHP x (1 mol KHP/204.22 g KHP) = 0.0124 mol KHP
23.22 mL NaOH x (M NaOH) = 0.0124 mol KHP
M NaOH = 0.0124 mol KHP/23.22 mL NaOH = 0.053 M NaOH
2.612 g KHP x (1 mol KHP/204.22 g KHP) = 0.0128 mol KHP
27.12 mL NaOH x (M NaOH) = 0.0128 mol KHP
M NaOH = 0.0128 mol KHP/27.12 mL NaOH = 0.047 M NaOH
The average concentration of NaOH solution is 0.049 M NaOH.
To calculate the molarity of NaOH, we can use the equation: mols KHP = mols NaOH.
First, let's calculate the number of moles of KHP (potassium hydrogen phthalate) using the formula: mols KHP = mass KHP / molar mass KHP.
For each trial, we have the following data:
- Trial 1: mass of KHP = 2.789 g
- Trial 2: mass of KHP = 2.543 g
- Trial 3: mass of KHP = 2.612 g
Next, we need to calculate the number of moles of NaOH for each trial using the equation: mols NaOH = volume NaOH x M NaOH.
For each trial, we have the following data:
- Trial 1: volume of NaOH used = 27.77 mL
- Trial 2: volume of NaOH used = 23.22 mL
- Trial 3: volume of NaOH used = 27.12 mL
Now, we can calculate the molarity of NaOH using the equation: M NaOH = mols NaOH / volume NaOH.
To find the average concentration of NaOH, we can calculate the average of the calculated molarity values obtained from each trial.
Please let me know if you would like me to perform the calculations for you.
To calculate the molarity of NaOH, we can follow these steps:
Step 1: Calculate the number of moles of KHP (potassium hydrogen phthalate) used in each trial.
Molar mass of KHP = 204.22 g/mol
Moles of KHP = mass of KHP / molar mass of KHP
Trial 1:
Moles of KHP = 2.789 g / 204.22 g/mol = 0.013641 mol
Trial 2:
Moles of KHP = 2.543 g / 204.22 g/mol = 0.012459 mol
Trial 3:
Moles of KHP = 2.612 g / 204.22 g/mol = 0.012782 mol
Step 2: Calculate the number of moles of NaOH used in each trial using the balanced equation:
KHP + NaOH → KNaP + H2O
From the equation, we can see that 1 mole of KHP reacts with 1 mole of NaOH.
Therefore, moles of NaOH = volume of NaOH x molarity of NaOH
Trial 1:
Moles of NaOH = 27.77 mL x M NaOH
Trial 2:
Moles of NaOH = 23.22 mL x M NaOH
Trial 3:
Moles of NaOH = 27.12 mL x M NaOH
Step 3: Since the moles of KHP and NaOH are equal, we can set up the following equation:
Moles of KHP = Moles of NaOH
Therefore, we can set up the following equations:
0.013641 mol = 27.77 mL x M NaOH
0.012459 mol = 23.22 mL x M NaOH
0.012782 mol = 27.12 mL x M NaOH
Now you can solve these equations to find the molarity (M) of NaOH.