I need help with this question, A 4-ohm resistor is connected in parallel with a 6 ohm resistor. What is the total resistance of this pair of resistors? I know the answer is 2.4 ohms, but I don't know how to get it. Please help!!
I know very little about electronics and even less about college physics,
so I went to google and entered "resistors in parallel" and within 15 seconds found the formula:
combined resistance = (R1 x R2)/(R1 + R2)
= 6x4/(6+4)
= 2.4
Three resistors having resistances of 1-ohm, 2-ohm and 3-ohm ,are connected in series to a 12-volt
battery having negligible internal resistance. .
A 60-ohm resistor,90-ohm and a 120-ohm resistors are connected in parallel, and the combination is
connected across a 12-volt source line.
To find the total resistance in a parallel circuit, you can use the formula:
1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...
In this case, R1 is the resistance of the first resistor (4 ohms) and R2 is the resistance of the second resistor (6 ohms). Substituting these values into the formula, we get:
1/RTotal = 1/4 + 1/6
To simplify this equation, we need a common denominator. The common denominator of 4 and 6 is 12, so we can rewrite the equation as:
1/RTotal = 3/12 + 2/12
Combining the fractions, we get:
1/RTotal = 5/12
Now, to solve for RTotal, we need to isolate it. Inverting both sides of the equation, we get:
RTotal = 12/5
Now, dividing 12 by 5, we find:
RTotal = 2.4 ohms
Therefore, the total resistance of the pair of resistors is 2.4 ohms.