Factor
(m + 4) (a – 5) + (m + 4) (a + 3)
I think this is correct
(a-5)+(a+3)
a+a = 2a
-5+3 = -2
(m+4) (2a–2)
Final Answer???
I think the answer is this because (m+4) is the common factor and then you add a+a to get 2a-2.
(m+4) (2a-2)???? is this correct?
That is right as far as it goes. However, you can still factor out the 2.
2(m+4)(a-1)
I hope this helps a little more. Thanks for asking.
To factor the given expression, (m + 4)(a - 5) + (m + 4)(a + 3), you correctly grouped the terms by (a - 5) and (a + 3). However, you need to apply the distributive property to each grouping in order to simplify further. Here's the step-by-step process:
1. Group the terms by (a - 5) and (a + 3):
(m + 4)(a - 5) + (m + 4)(a + 3)
2. Apply the distributive property to each grouping:
ma - 5m + 4a - 20 + ma + 3m + 4a + 12
3. Combine like terms:
ma + ma + 4a + 4a - 5m + 3m + 12 - 20
4. Simplify the expression further:
2ma + 8a - 2m - 8
So, the correct factorized form of the given expression is:
2ma + 8a - 2m - 8