Suppose 1.0 mol of substance A reacts with 1.0 mol of substance B. to produce 2.0 mol of substance C. In a reaction, 2.4 mol of substance A is allowed to react with 2.1 mol of substance B.

What amount in moles of substance c is produced?

To determine the amount of substance C produced in the reaction, we need to use the concept of stoichiometry. The given stoichiometry indicates that 1.0 mol of substance A reacts with 1.0 mol of substance B to produce 2.0 mol of substance C.

First, we need to calculate the amount of limiting reactant in the given reaction. The limiting reactant is the one that is completely consumed and determines the amount of product that can be formed. To do this, we compare the number of moles of A to B and determine which reactant is in excess.

Given:
- Moles of A = 2.4 mol
- Moles of B = 2.1 mol

To find the amount of substance C produced, we must determine the limiting reactant.

Assuming A is limiting, we need 1.0 mol of B to react with it. However, we only have 2.1 mol of B, which is sufficient. Therefore, B is not the limiting reactant.

Then, let's calculate the amount of C produced using the balanced equation:
- 1.0 mol of A reacts to produce 2.0 mol of C

Since A is the limiting reactant, the amount of C produced is proportional to the amount of A used. Therefore, we can set up a proportion to find the amount of C produced.

(2.0 mol of C / 1.0 mol of A) = (x mol of C / 2.4 mol of A)

Solving for x, we get:
x = (2.0 mol of C / 1.0 mol of A) * (2.4 mol of A / 1)

x = 4.8 mol of C

Hence, 4.8 moles of substance C is produced.