hoq to solve equations using the quadratic forlmula. ex. 2Xsquare -7X +5=0
please ehlp
assistance needed
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-b(plus or minus)(the square root ofb^2-2(a)(c)
all divided by 2a
a=2 , b=-7 , c=5
sub into the formula Brianna just gave you, which actually has a typo in it, should be
x = (-b ± √(b^2 - 4ac)/(2a)
To solve quadratic equations using the quadratic formula, you can follow these steps:
Step 1: Identify the coefficients:
In the equation 2x^2 - 7x + 5 = 0, the coefficients are:
a = 2, b = -7, and c = 5.
Step 2: Write the quadratic formula:
The quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a).
Step 3: Substitute the coefficients into the quadratic formula:
For your equation, substitute the values of a, b, and c into the quadratic formula:
x = (-(-7) ± √((-7)^2 - 4(2)(5))) / (2(2)).
Simplifying further:
x = (7 ± √(49 - 40)) / 4.
x = (7 ± √9) / 4.
Step 4: Simplify the expression:
The square root of 9 is 3:
x = (7 ± 3) / 4.
Step 5: Find the solutions:
Now, you have two possibilities for x:
x₁ = (7 + 3) / 4 = 10 / 4 = 2.5.
x₂ = (7 - 3) / 4 = 4 / 4 = 1.
Therefore, the solutions to the equation 2x^2 - 7x + 5 = 0 are x = 2.5 and x = 1.