# Algebra

I need to simplify this.

(2^-1 . 7^-4)^-2

I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!

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1. (2^-1 . 7^-4)^-2
= (2^2)(7^8)
= 23059204

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posted by Reiny
2. Those aren't any of my choices Here is what i got

2^2 . 7^8

2^5 . 7^5

1/2^5 . 7^5

1/2^2 . 7 ^8

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posted by Laurie
3. sorry I went to the effort of calculating
2^2 . 7^8 for you.

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posted by Reiny
4. Thanks! That is what I thought, but why is this the answer? How does the probelm work it self out to be like that?

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posted by Laurie
5. multiply each of the inside terms by the outside term.

2^-1*1^-2 = combine exponents = 2^2

7^-4*1^-2 = combine exponents = 7^8

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