Algebra

I need to simplify this.

(2^-1 . 7^-4)^-2

I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!

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asked by Alicia
  1. (2^-1 . 7^-4)^-2
    = (2^2)(7^8)
    = 23059204

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    posted by Reiny
  2. Those aren't any of my choices Here is what i got

    2^2 . 7^8

    2^5 . 7^5

    1/2^5 . 7^5

    1/2^2 . 7 ^8

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    posted by Laurie
  3. sorry I went to the effort of calculating
    2^2 . 7^8 for you.

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    posted by Reiny
  4. Thanks! That is what I thought, but why is this the answer? How does the probelm work it self out to be like that?

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    posted by Laurie
  5. multiply each of the inside terms by the outside term.

    2^-1*1^-2 = combine exponents = 2^2

    7^-4*1^-2 = combine exponents = 7^8

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