Calculate the number of grams in the following :[149.096 g/mole]

8.55 moles of (NH4)3PO4

IT WOULD BE NICE IF I CAN GET STEP BY STEPS TO GET ANSWER !!!

First add up the molarity of your compound

3N= 42.0201
12H = 12.09528
P= 30.97376
4O = 63.99600

Add those number up and you should get 149.08 (I rounded).

(8.55mole) * (149.09g/1mole) = ??

Dang it! I did not know what the :[149.096 g/mole] meant until I looked back again. Apparently they gave your the total mass of the compound! I went through and did all that work for nothing!

Anyways your answer should not be off by much, but if you it to be as accurate as the problem says than use replace the grams

Also, you are not adding up the molarity of the compound. Molarity is numer of moles of solute per liter of solution.

To calculate the number of grams in 8.55 moles of (NH4)3PO4, you need to use the molar mass of (NH4)3PO4 and the given number of moles.

Step 1: Find the molar mass of (NH4)3PO4.
(NH4)3PO4 consists of three ammonium ions (NH4+) and one phosphate group (PO4^3-). The molar masses of the constituent elements are as follows:
- Nitrogen (N): 14.01 g/mole
- Hydrogen (H): 1.008 g/mole
- Phosphorus (P): 30.97 g/mole
- Oxygen (O): 16.00 g/mole

For the ammonium ions:
1 nitrogen (N) with molar mass 14.01 g/mole
4 hydrogens (H) with molar mass 4 × 1.008 g/mole

For the phosphate group:
1 phosphorus (P) with molar mass 30.97 g/mole
4 oxygens (O) with molar mass 4 × 16.00 g/mole

Summing up the masses:
(1 × 14.01 g/mole) + (4 × 1.008 g/mole) + (1 × 30.97 g/mole) + (4 × 16.00 g/mole)

Calculate the molar mass of (NH4)3PO4.

Step 2: Calculate the number of grams.
To calculate the number of grams, multiply the number of moles (8.55) by the molar mass of (NH4)3PO4 (from step 1).

8.55 moles × (molar mass of (NH4)3PO4 g/mole)

Evaluate this calculation, and you will find the number of grams in 8.55 moles of (NH4)3PO4.