Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
What is the period of y=5 cos pi x and how do you find it?
1 answer
for y = a cos kx, the period is 2pi/k
so your period is 2pi/pi
= 2
You can
ask a new question
or
answer this question
.
Similar Questions
Explain how do you find the period of Y = cos(6x) from your graph. what is the period of Y= cos(6x) in radians?
Top answer:
when 6 x = 2 pi, that is a period change in x = pi/3 is once around
Read more.
how to find the period of y = cos(6x)from your graph. what is the period of y=cos(6x) in radians?
Top answer:
The period is 2 pi in radians for any old trig periodic function.
Read more.
how to find the period of y = cos(6x)from your graph. what is the period of y=cos(6x) in radians?
Top answer:
To find the period of a trigonometric function, you need to examine its graph. In this case, you are
Read more.
how do i find out what the amplitude, period, h, k and midline of problems
1) y= sin (x-5)=7 2) y=3 cos (x- pie) -1 3) y= Sin3x+4
Top answer:
To find the amplitude, period, h, k, and midline of a function, you need to understand their
Read more.
Find the roots of z^6 + 1 and hence resolve z^6 + 1into read quadratic factors; deduce that
cos3x = 4[cos(x) -cos(pi/6)][(cos(x)
Top answer:
To find the roots of the equation z^6 + 1 = 0, we can use the fact that any complex number can be
Read more.
Find the roots of z^6 + 1 and hence resolve z^6 + 1into read quadratic factors; deduce that
cos3x = 4[cos(x) -cos(pi/6)][(cos(x)
Top answer:
To find the roots of the equation z^6 + 1, we can rewrite it as a difference of squares: z^6 + 1 =
Read more.
Question: Trying to find cos π/12, if cos π/6 = square root 3 over 2, how to find cos π/12 using DOUBLE angle formula?
This is
Top answer:
you got it backwards π/12 = (1/2) of π/6 using cos 2A = cos^2 A - sin^2 A = 2cos^2 A - 1 so cos
Read more.
13. What is the equation of a cosine function with amplitude 3, transition point (−1, 1), and period p?
A. y = p cos [3(x −
Top answer:
13. amplitude 3: 3cos(...) period p: 3cos(2pi(...)/p) ... translate by (-1,1): 3cos(2pi(x+1)/p) + 1
Read more.
Given:
cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list
Top answer:
if cos u=3/5 cos v=5/13 then sin u=4/5 and sin v=12/13 then sin(v+u)=sinv cos u+cos v sin u
Read more.
Evaluate the trigonometric function using its period as an aid.
cos 5pi how would i go about finding the period and what is a
Top answer:
Period: When does it repeat itself? Cosine repeats each 2PI, so cos5Pi= cos(5PI-2PI)=cos3PI=
Read more.
Related Questions
Find the period and the amplitude of the periodic function.
y=-4 cos 8x
Find the period and the amplitude of the periodic function y= -5 cos 6x
a. period = 1/3pi, amplitude = -5 b. period = 1/6pi,
Which cosine function has maximum of 4, a minimum of -4, and a period of 2pi/3?
A. y=4 cos 3 theta B. y= 4 cos 2 theta/3 C. y=4
Express each of the following in terms of the cosine of another angle between 0 degrees and 180 degrees:
a) cos 20 degrees b) cos
Write an equation for the translation of the function. y = cos x; translated 6 units up
A. y = cos x- 6 B. y = cos(x + 6) C.
Find the measure of the acute angle x, if :
sin(x)=0.0175; sin(x)=0.5015; cos(x)=0.06814; cos(x)=0.0670. I know that
4. Find the exact value for sin(x+y) if sinx=-4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant.
5. Find the exact
Find the period, range, and amplitude of the cosine function.
y = –4 cos 8x A. period = 1/4, range = –4 ≤ y ≤ 4,
Evaluate the two trigonometric functions using its period as an aid.
1. cos (9pi/2) = ? Ans: 0 2. cos (-9pi/2) = ? Ans: 0 I think
a sound wave is modeled with the equation y=1/4 cos 2pi/3 theta.
a.find the period.explain b.find the amplitude.explain