Science and medicine. Find the time required for an object to fall to the ground from a building that is 1400 ft high.
using the formula : t = 1/4 radical (s)
t=1/4 radical 1400
t= 10 radical 14*1/4
t= 5 radical 14 /2
what are I doing wrong I am suppose to be getting minutes and seconds
Here is how you do it. Start with the equation for how far something falls in time t.
1400 ft = (1/2) g t^2
"g" is the acceleration of gravity, which is 32.2 ft/s^2
t^2 = 2800/g = 86.7 s^2
t = sqrt 86.7 = 9.3 seconds
can you explain to me how you got the 2800 /g I got lost there
Sure, let's break it down step by step.
The equation for the distance an object falls due to gravity is given by:
s = (1/2) g t^2
Where:
s is the distance fallen (in this case, 1400 ft)
g is the acceleration due to gravity (approximately 32.2 ft/s^2)
t is the time it takes to fall (what we're trying to find)
To solve for t, we rearrange the equation as follows:
2s = g t^2
Dividing both sides by g gives us:
2s / g = t^2
Now, substitute the given values into the equation:
2(1400 ft) / (32.2 ft/s^2) = t^2
This simplifies to:
2800 ft / 32.2 ft/s^2 = t^2
The units ft and ft/s^2 cancel each other out, leaving us with:
t^2 = 86.7 s^2
Next, take the square root of both sides to find t:
t = √(86.7 s^2) ≈ 9.3 seconds
So, the time required for the object to fall from a building that is 1400 ft high is approximately 9.3 seconds.