Could some one tell m if this is right?

1)Does currend flow through a resistor or across a resistor in a series circuit? THROUGH

2) Is a voltage establishes through a resistor or across ? ACROSS

PARALLEL CIRCUITS

1)there is a voltage drop of 6volts across each 2-Ù resistor

the currtent in each resistor is _____A
6A right or wrong?

The current through the battery is the sum of the currents in the resistors __A
6 amps right or wrong?

the first two correct.

If the resistors in parallel are 2 ohm each, then the current in each resistor is 3amps, and total current is six amps.

thanks

1) In a series circuit, the current flows through a resistor. This can be explained by understanding the nature of a series circuit, where the components are connected one after another in a single pathway. The current passes through each component sequentially, and thus, it flows through the resistor.

To verify this, you can apply Ohm's Law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R), represented by the equation V = IR. In a series circuit, the total voltage of the circuit is distributed across the various components, so the voltage across the resistor can be determined by subtracting the voltage of other components (if any) from the total voltage of the circuit.

2) In a series circuit, the voltage is established across a resistor. This can be understood by considering the fact that voltage represents the potential difference between two points in a circuit. In a series circuit, the total voltage of the circuit is divided among the various components, including the resistor. Each component experiences the same voltage drop, and thus the voltage is established across the resistor.

PARALLEL CIRCUITS

1) In a parallel circuit, each resistor has the same voltage drop across it. In the given case, there is a voltage drop of 6 volts across each 2-Ω resistor. To find the current in each resistor, you can apply Ohm's Law, where V = IR. Rearranging the equation to solve for current, you have:

I = V / R
I = 6V / 2Ω
I = 3A

Therefore, the current in each resistor is 3 amps.

2) In a parallel circuit, the current through the battery is the sum of the currents in the resistors. This can be explained by considering that in a parallel circuit, the current has multiple pathways to follow. Each resistor allows a certain amount of current to flow through it, and the sum of these currents equals the total current provided by the battery.

In this case, since the current in each resistor is 3 amps, and there is only one resistor in this parallel circuit, the total current through the battery would also be 3 amps.

Therefore, the current through the battery is 3 amps.