The specific heat capacity of the lava is 1600 J kg -1 degrees Celsius -1 .
When all the erupted lava cools from the eruption temperature of 1050 degrees Celsius to 15 degrees Celsius, the heat released is 2 x 10 15 J.
Calculate a value for the total mass of lava that erupted. Give your answer in scientific notation.
The equation for this is q =cm deltaTem
q = heat transferred
c= specific heat
m = mass
delta temperature = change in temperature
2 x 1015 = 1600 x (1050-15) x m
M = 2x 1015 = 1207729469g
1600 x 1035
can sum1 help me is this correct??
the 2 x 10 is meant to be 2 x 10 ^ 15 likewise same for the rest of 2 x 1015
TRANSPOSE THE EQUATION FOR MASS.PLUG NUMBERS IN AND GIVE ANSWER TO *ONE* SIG FIG USING SCIENTIFIC NOTATION.
this is part of an OU exam question if copied directly it is classed as plagarism thius is is being monitored by the ou
dont copy directly it is a form of cheating & not worth failing an exam over it
To calculate the total mass of lava that erupted, we can rearrange the equation:
q = cmΔT
where q is the heat transferred, c is the specific heat, m is the mass, and ΔT is the change in temperature.
Plugging in the given values, we have:
2 x 10^15 J = (1600 J kg^-1°C^-1) x (1050°C - 15°C) x m
Simplifying the equation:
2 x 10^15 J = (1600 J kg^-1°C^-1) x 1035°C x m
Now, to solve for m, we can divide both sides of the equation by (1600 J kg^-1°C^-1) x 1035°C:
m = (2 x 10^15 J) / [(1600 J kg^-1°C^-1) x 1035°C]
Evaluating the expression:
m ≈ 0.745 x 10^12 kg
Therefore, the total mass of lava that erupted is approximately 7.45 x 10^11 kg (in scientific notation and rounded to one significant figure).