PLEASE HELP!!!
A standard doorway measures 6 feet 8 inches by 3 feet. What is the largest dimension that will fit through the doorway without bending???
o and i also need work shown
Do you mean what length of stick or pole would fit through a doorway? If so, find the hypotenuse of a triangle whose bases measures 6 ft, 8 inches and 3 feet.
Ok, i got that but now we have 3squared + 6ft 8in squared = c squared , but how do you do 6ft 8in. squared?
ahh, the perils of that archaic imperial system of measurement.
you either have to convert all your measurements to inches or to feet.
in the metric system you would simply have to move some decimals around
I think I'm a bit late with these answers but here they are :)
1. 62.5 square units
2. 268 square centimeters
3. 58 square units
4. 45m2
5. 412 ft.2
To square 6ft 8in, first convert it to inches.
1 foot is equal to 12 inches, so 6ft is equal to 6 * 12 inches, which is 72 inches.
Therefore, 6ft 8in is equal to 72 inches + 8 inches, which is 80 inches.
Now you can square 80 inches: 80^2 = 6400 inches^2.
Remember, when working with units that were previously squared, the resulting units will be squared as well. So in this case, the answer is 6400 inches^2.
Now you can proceed with solving the equation for the hypotenuse:
3^2 + 6400 inches^2 = c^2
Simplifying, you get:
9 + 6400 inches^2 = c^2
Next, add the numbers:
6409 inches^2 = c^2
To find the value of c, take the square root of both sides of the equation:
√(6409 inches^2) = √(c^2)
Cancelling the square on the right side, you get:
c = √(6409) inches
Evaluating the square root:
c ≈ 80.06 inches
Therefore, the largest dimension that will fit through the doorway without bending is approximately 80.06 inches.