How many milliliters of glacial acetic acid are needed to prepare 2.0 L of 10.0% volume/volume acetic acid?
To find the amount of glacial acetic acid needed to prepare 2.0 L of 10.0% volume/volume acetic acid solution, we can use the following formula:
Amount of glacial acetic acid (in mL) = Volume of final solution (in L) × % concentration
Let's substitute the values into the formula:
Amount of glacial acetic acid (in mL) = 2.0 L × 10.0%
To calculate the result, we need to convert the percentage concentration to a decimal:
Amount of glacial acetic acid (in mL) = 2.0 L × 0.10
Finally, we can calculate the value:
Amount of glacial acetic acid (in mL) = 0.20 L or 200 mL
Therefore, you will need 200 mL of glacial acetic acid to prepare 2.0 L of 10.0% volume/volume acetic acid solution.
To determine the amount of glacial acetic acid needed to prepare a certain volume and concentration of acetic acid solution, we can use the formula:
(amount of glacial acetic acid) = (desired volume of acetic acid solution) x (desired concentration of acetic acid)
In this case, the desired volume of acetic acid solution is 2.0 L, and the desired concentration is 10.0% (volume/volume). To calculate the amount of glacial acetic acid required, follow these steps:
Step 1: Convert the desired concentration from a percentage to a decimal:
10.0% = 10.0/100 = 0.1
Step 2: Apply the formula mentioned above:
(amount of glacial acetic acid) = 2.0 L x 0.1
Step 3: Perform the calculation:
(amount of glacial acetic acid) = 0.2 L
Since we want the answer in milliliters, we can convert the result:
0.2 L = 0.2 x 1000 mL = 200 mL
Therefore, you would need 200 milliliters of glacial acetic acid to prepare 2.0 liters of a 10.0% volume/volume acetic acid solution.