Multiplying Binomials
(b-6)*(b+3)
(b-6)(b+3)
use FOIL:
b*b
b*3
-6*b
-6*3
add them together to get:
b^2 - 3b - 18
You distribute the first set of brackets.
When you have equations like this you should pretend there are no brackets around the first equation.
b-6 (b+3)
first you distribute b into the brackets.
(b)(b) = b^2
then b to 3
(b)(3) = 3b
then you distribute the -6 to both...
(-6)(b) = -6b
then -6 to 3...
(-6)(3) = -18
then you add them together...
b^2-3b-18
:)
To multiply binomials, such as (b-6)*(b+3), we can use the distributive property. The distributive property states that multiplying a term by the sum of two or more terms is the same as multiplying the term separately by each term in the sum, and then adding the products together.
Here's how to do it step by step:
1. Start by multiplying the first terms of each binomial together. In this case, we multiply 'b' from the first binomial and 'b' from the second binomial. The result is b^2.
2. Next, multiply the first term from the first binomial with the second term from the second binomial. In this case, multiplying 'b' from the first binomial with '3' from the second binomial gives us 3b.
3. Then, multiply the second term from the first binomial with the first term from the second binomial. In this case, multiplying '-6' from the first binomial with 'b' from the second binomial gives us -6b.
4. Finally, multiply the second terms of each binomial together. In this case, multiplying '-6' from the first binomial with '3' from the second binomial gives us -18.
5. Now, combine the products obtained in steps 1, 2, 3, and 4. We have b^2 + 3b - 6b - 18.
6. Simplify the expression by combining like terms. In this case, combining '3b' and '-6b' gives us -3b.
7. The final result is b^2 - 3b - 18.
Therefore, (b-6)*(b+3) equals b^2 - 3b - 18.