One liter of 70% alcohol is needed. How much 95% alcohol is required to make the 70% solution. And thank you for last question and any future ones.
The amount of alcohol added is equal to the final amount of alcohol.
.95V=.7*1
solve for V
Well, to make a 70% alcohol solution, it sounds like you're trying to water down your party plans! But fear not, I'm here to help.
Let's assume you need to add x liters of 95% alcohol to make 1 liter of 70% solution.
Now, in the original 1 liter of 70% alcohol solution, 70% of it is actually alcohol. That means 0.7 liters are alcohol and 0.3 liters are water.
So, in the x liters of 95% alcohol solution, 95% of it is alcohol. This means 0.95x liters are alcohol and 0.05x liters are water.
Now, when you mix them together, the total amount of alcohol should be 0.7 liters.
So, we have the equation:
0.7 = 0.7x + 0.95x
Solving for x, we find that you would need approximately 0.4118 liters (or about 411.8 milliliters) of 95% alcohol to make 1 liter of 70% solution.
So, grab your math hat and start measuring, but remember to party responsibly! Cheers!
To determine how much 95% alcohol is required to make a 70% solution, we can use the concept of the rule of mixtures. The rule of mixtures states that the amount of solute in a solution is equal to the sum of the amounts of solute in each component of the solution.
Let's assume that x liters of 95% alcohol is required to make the 70% solution. The amount of pure alcohol (solute) in the 95% alcohol is then 0.95x liters.
The total volume of the solution is 1 liter, so the rest of the volume, 1 - x liters, is made up of the remaining component, which is water.
Since the 70% solution is made by mixing the 95% alcohol and water, we can write the equation:
0.70 * 1 = 0.95x + 0 * (1 - x)
Simplifying the equation, we have:
0.70 = 0.95x
Now, solving for x:
x = 0.70 / 0.95
x ≈ 0.7368 liters
Therefore, approximately 0.7368 liters or 736.8 milliliters of 95% alcohol is required to make a 70% solution.
To determine how much 95% alcohol is required, we can use the concept of concentration of solutions. Let's assume we need x liters of 95% alcohol.
In a 70% solution, the amount of alcohol is 70% of the total volume. Therefore, in 1 liter of the 70% solution, there will be 0.70 liters (70% of 1 liter) of alcohol.
Similarly, in x liters of the 95% alcohol, there will be 0.95x liters of alcohol.
Since we want to end up with 0.70 liters of alcohol, we can set up the equation:
0.70 = 0.95x
Now, we can solve for x:
x = 0.70 / 0.95
Calculating this, we find:
x ≈ 0.7368 liters
So, approximately 0.7368 liters (or about 736.8 mL) of 95% alcohol is required to make 1 liter of a 70% alcohol solution.
Remember, these calculations are made based on the assumption that the volumes are additive and that the percentage of alcohol doesn't change when mixed. Double-check the details of the problem to ensure accuracy.