Algebra

The volume of a rectangular box is given by the formula V = lwh, where l is length, w is width, and h is height. What happens to the volume if the length and height are doubled and the width is tripled?

I don't know how to solve this problem at all.

Thank you for your help!

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  1. new volume = (2h)(2l)(3w) = 12lwh

    so the volume is 12 times as big

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  2. vol = l*w*h
    the question is that
    l is doubled to give 2l
    h is doubled to give 2h and
    w is tripled to give 3h.

    so the new vol = (2l)*(2h)*(3w) = 12*l*w*h
    so 'new vol' = 12*old vol

    Hope that helps

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  3. I really don't understand this honors algebra

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