Write an equation of the line containing the given point and parallel to the given line. Express yur answer in the form y=mx+b

(7,9) x+4y=5
The equation of the line is y=

Here is a clue for the question:

Parallel lines have the same slope.

You have 1 line - find its slope.

Hope that helps

I have tried to work this problem can not get this answer. I am sorry I was a problem

ok, you have a line x + 4y = 5

to find the slope re-write in the form
y = mx + c
where m is the slope and c is a constant

in the above line m = -1/4.

So we want the equation of a line parallel to the above line but goes through the point (7,9).

As I said above parallel lines have the same slope so now we have a point and a slope. That's all we need to get the equation.
Just sub in m = -1/4 and (x1,y1) = (7,9)
into y - y1 = m(x - x1)

and tidy up.

That's it.

Hope that clears things up

To find the equation of a line parallel to the given line and passing through the given point, we need to use the fact that parallel lines have the same slope.

First, let's rewrite the given line, x + 4y = 5, in slope-intercept form (y = mx + b) where m represents the slope of the line.

x + 4y = 5
4y = -x + 5
y = (-1/4)x + 5/4

From this, we can see that the slope of the given line is -1/4.

Since the line we want to find is parallel to the given line, it will also have a slope of -1/4. Now, we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is y - y1 = m(x - x1), where (x1, y1) represents the given point.

Using the point (7, 9) and the slope -1/4, we can substitute these values into the point-slope form and simplify the equation.

y - 9 = -1/4(x - 7)

Expanding and rearranging, we get:

y - 9 = (-1/4)x + 7/4

To isolate y, we can add 9 to both sides:

y = (-1/4)x + 7/4 + 9
y = (-1/4)x + 7/4 + 36/4
y = (-1/4)x + 43/4

Therefore, the equation of the line parallel to x + 4y = 5 and passing through the point (7, 9) is y = (-1/4)x + 43/4.