how do i solve this?!?!
4x-2y=32
-3x-5y=-11
I would multiply the top equation by 5, and the bottom equation by 2
20x-10y=160
-6x-10y=-22
then subtract the bottom equation (remember to change the signs)
26x=182 solve for x.
alright i got x=7 but now what do i do?
Go back to either of the original equations, put in 7 for x, and solve for y.
so for example
4(7)-2y=32 or -3(7)-5y=-11
and then it equals 28-2y=32 or
-21-5y=-11
then what from their this is driving me insane!
add 21 to each side.
divide each side by -5
I think the answer is y=2,but you better check.
Yep, 2 is almost right, but not quite. Check to see why.
i honestly cannot not get this problem, i guess it wont kill me to miss 1 assignment
-2x+3y=-12
2x+y=10
To solve these equations, you can use the method of substitution or the method of elimination. Let's solve them using the method of substitution.
Step 1: Solve one equation for one variable in terms of the other variable.
Let's choose the first equation to solve for x in terms of y:
4x - 2y = 32
4x = 2y + 32
x = (2y + 32)/4
x = (y + 16)/2
Step 2: Substitute the expression for x in terms of y into the second equation:
-3x - 5y = -11
-3((y + 16)/2) - 5y = -11
Step 3: Simplify and solve for y:
-3(y + 16)/2 - 5y = -11
-3(y + 16) - 10y = -22
-3y - 48 - 10y = -22
-13y - 48 = -22
-13y = 26
y = -2
Step 4: Substitute the value of y back into the expression for x to find its value:
x = (y + 16)/2
x = (-2 + 16)/2
x = 14/2
x = 7
So, the solution to the system of equations is x = 7 and y = -2.