I need to factor this equation completely. CAn someone help me please.
2x^4 + 16x
first take out a common factor of 2x
so
2x^4 + 16x
= 2x(x^3 + 8)
now recall the factoring of the sum of cubes:
A^3 + B^3 = (A+B)(A^2 - AB + B^2)
apply this to the part in brackets.
(2x^4+16x)(2x^2-2x(16)+16x^2)
would this be correct?
no,
you could tell immediately that you are wrong by merely multiplying the first two terms.
You would get 4x^6 ... wouldn't you?
Did you not read my reply??
yes.
I see my mistake..
if you could please break this down for me ../
like not just give me the answer but help me understand it becuase I have schol tommrow..and really want to understand it better. pelase.I would really apreicatre it.
PLEASE PLEAESE HELP
there is nothing more to break down
I gave you
2x(x^3 + 8) and then I gave you the formula for the sum of cubes.
the next step would be to write down the answer
= 2x(x+2)(x^2 - 2x + 4)