The potential differnece across a resistor is 4.4 * 10^2 V. If the resistance of the resistor is 1.8 k ohms, how much current flows throught the resistor?
R=1.8 k ohms
I=?
4.4*10^2 V
V=IR
I=V/R
= 4.4 * 10^2
___________ = 2.44*10
1.8 * 10^
24.4 A
is this done correctly?
Of course not.
440 volts divided by 1800 ohm is not 24 amps.
is it .24 amps?
yes, or 240mA
which answre would be apropriat for this question
240mA
or .24 amps
MC, either is correct. The most common usage is probably 240mA, but it is no more correct than .24 A
ok, thanks
To solve for the current flowing through the resistor, you correctly used Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R).
In this case, the potential difference across the resistor is given as 4.4 * 10^2 V (or 440 V in standard form) and the resistance is 1.8 k ohms (or 1800 ohms in standard form).
Using the formula I = V/R, you correctly substituted the given values into the equation to get I = 4.4 * 10^2 / 1.8 * 10^3.
To divide the exponents, you subtract the exponent of the denominator from the exponent of the numerator (10^2 - 10^3 = -1).
To calculate the actual value, you multiply the coefficient of the numerator (4.4) by 10 raised to the power of -1.
Therefore, the result is 2.44 A (or 2.44 amperes).
In summary, your calculation is correct, and the current flowing through the resistor is indeed 2.44 A.