A titration of 15.0 cm3 of household ammonia, NH3, required 38.57 cm3 of 0.78M HCl. Calculate the molarity of the ammonia.
Please show steps so that I may unders tand how solve this. Thank you
To find the molarity of ammonia (NH3), we need to use the equation:
M1V1 = M2V2
Where:
M1 = molarity of HCl solution
V1 = volume of HCl solution
M2 = molarity of ammonia
V2 = volume of ammonia solution
Given:
M1 = 0.78 M (molarity of HCl solution)
V1 = 38.57 cm^3 (volume of HCl solution)
V2 = 15.0 cm^3 (volume of ammonia solution)
Let's substitute the values into the equation:
0.78 M x 38.57 cm^3 = M2 x 15.0 cm^3
Simplifying the equation, we have:
30.12 = 15M2
Now, we can solve for M2 by dividing both sides of the equation by 15:
M2 = 30.12 / 15
M2 = 2.008 M
Therefore, the molarity of the ammonia solution is 2.008 M.